Answer :
Answer:
4.76 m/s²
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
[tex]v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{v-0}{2}\\\Rightarrow a=\frac{v}{2}\\\Rightarrow v=2a[/tex]
Now, this velocity will be the velocity of the later 11.5-2 = 9.5 seconds with no acceleration so,
Distance = Speed × Time
⇒ D = 2a×9.5 = 19a m
Distance traveled during the first two seconds is
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow s=0\times 2+\frac{1}{2}\times a\times 2^2\\\Rightarrow s=2a\ m[/tex]
Total distance = 100 m = Distance traveled in 2 seconds + Distance traveled in the 9.5 seconds
100 = 2a+19a
[tex]\\\Rightarrow 100=21a\\\Rightarrow a=4.76\ m/s^2[/tex]
Acceleration during the first two seconds is 4.76 m/s².