Answer :
Answer:
No the distance traveled in last 0.1 s is not same as that the distance traveled in first 0.1 s
so it will cover more distance in last 0.1 s then the distance in first 0.1 s
Explanation:
As we know that when stone is dropped from the diving board then its velocity at the time of drop is taken to be ZERO
so here we can say that its displacement from the top position in next 0.1 s is given as
[tex]d_1 = v_y t + \frac{1}{2}at^2[/tex]
[tex]d_1 = 0 + \frac{1}{2}(9.81)(0.1)^2[/tex]
[tex]d_1 = 0.05 m[/tex]
Now during last 0.1 s of its motion the stone will attain certain speed
so we will have
[tex]d_2 = v_y(0.1) + \frac{1}{2}(9.81)(0.1)^2[/tex]
[tex]d_2 = 0.1 v_y + 0.05 m[/tex]
so it will cover more distance in last 0.1 s then the distance in first 0.1 s