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consider the equation cx-d=2x+4. Replace the c in the equation with 2. For what value of d would the equation have infinitely many solutions? explain.

Answer :

Answer:

(*-4)squared=xsquared+cx+d

Step-by-step explanation:

For the value of d = -4, the system has infinitely many solutions.

What is a system of equation?

A system of equations is a set or collection of equations that you deal with all together at once. For a system to have a unique solution, the number of equations must equal the number of unknowns.

For the given situation,

The equation cx-d = 2x+4.

Substitute c = 2 in the equation, we get

⇒ [tex]2x-d=2x+4[/tex]

⇒ [tex]d=2x-2x-4[/tex]

⇒ [tex]d=-4[/tex]

Now substitute d in the above equation,

⇒ [tex]2x-(-4)=2x+4[/tex]

⇒ [tex]2x+4=2x+4[/tex]

Here, LHS = RHS. Both the equations are same.

Thus the system has infinitely many solutions.

Hence we can conclude that for the value of d = -4, the system has infinitely many solutions.

Learn more about the system of equation here

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