Answer:
The position of the car at t = 1.5 s is at -8.1625 meters
Explanation:
The initial position of the car is 3.2 meters
The initial velocity is -8.4 m/s
The constant acceleration is 1.1 m/s²
We need to find the final position of the car at the time t = 1.5 seconds
The displacement s = final position - initial position
[tex]s=ut+\frac{1}{2}at^{2}[/tex], where u is the initial velocity, a is the
constant acceleration and t is the time
So we can find the final velocity by using the rule:
final position - initial position = [tex]ut+\frac{1}{2}at^{2}[/tex]
initial position = 3.2 meters , u = -8.4 m/s , a = 1.1 ²m/s , t = 1.5 s
Substitute these values in the rule
final position - 3.2 = [tex](-8.4)(1.5)+\frac{1}{2}(1.1)(1.5)^{2}[/tex]
final position - 3.2 = -12.6 + 1.2375
final position - 3.2 = -11.3625
add 3.2 for both sides
final position = -8.1625
That means the car is at 8.1625 meters in opposite direction
The position of the car at t = 1.5 s is at -8.1625 meters
