Answer :
Answer:
(a) you do a work on the piston: 35.34 (Joules) and (b) Average Force that you exert on the piston is: 117.81 (N)
Explanation:
We need to know that the work do it for a piston or boundary work of closed system is: [tex]W=P*DeltaV[/tex] where W is the work, P is the pressure and delta_V is the change in the volume. Now we need to remember that the volume for a piston is the same as:[tex]Volumen=\frac{\pi *diameter^{2} }{4} *L[/tex] where L is the maximum stroke or length, so the piston volume is:[tex]Volume=\frac{\pi*0.025^{2}}{4}*0.3=0.000147(metres^{3} )[/tex] therefore, piston's work is:[tex]W=2.4*10^{5} *0.000147=35.34(Jolues)[/tex]. Then we are going to calculate the average force so we need to know that [tex]P=\frac{F}{A}[/tex] where P is the pressure, F is the force and A the area in this case the piston´s area, so [tex]A=\frac{\pi*diameter^{2}}{4}= \frac{\pi*0.025^{2} }{4} =0.00049(metres^{2})[/tex] and replacing values we get: [tex]F=P*A=2.4*10^{5}*0.00049=117.81 (N)[/tex]