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To determine whether a shiny gold-colored rock is actually gold, a chemistry student decides to measure its heat capacity. She first weighs the rock and finds that it has a mass of 4.7 g. She then finds that, upon absorption of 52.7 J of heat, the rock undergoes a rise in temperature from 25 ∘C to 57 ∘C. Find the specific heat capacity of the substance comprising the rock.

Answer :

joseaaronlara

Answer:

The answer to your question is: Cp = 350.4 J/ kg°C

Explanation:

Data

mass = m = 4.7 g   convert grams to kilograms  0.0047 kg

heat= Q = 52.7 J

Temperature = 25 - 57 °C

Formula

Q = mCpΔT    solve for Cp

Cp = Q / mΔT

Process

Cp = 52.7 / [(0.0047)(57 - 25)]            Substitution

Cp = 52.7 / 0.1504                                

Cp = 350.4 J/ kg°C

CroftersJelly

Answer:

0.35 J/gc

Explanation:

The relationship among heat ( q ), mass ( m ), specific heat ( Cs ), and temperature change ( ΔT ) is as follows:  q=mCsΔT . Isolating and solving for  Cs  requires that the equation to be rearranged. The calculation of the specific heat capacity of this substance is summarized as follows:

Cs=qmΔT=52.7 J(4.7 g)(57∘C−25∘C)

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