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Ejay bought a pack of peanut bars from the neighborhood store. He ate 3 of the cont of the contents immediately. He gave 20 pieces to his sister Aileen. Then he ate emaining bars. of the remaining ba If he has 25 peanut bars left later, how many bars did the pack originally contain?

Answer :

TaeKwonDoIsDead

Answer:

105

Step-by-step explanation:

Complete Question:

"Ejay bought a pack of peanut bars from the neighborhood store. He ate 1/3 of the context immediately. He gave 20 pieces to his sister Aileen. Then he ate 1/2 of the remaining bars. If he has 25 peanut bars left after, how many bars did the pack originally contain?"

Let original amount be x

He ate 1/3 immediately so remaining

x - 1/3x

He gave 20 to Aileen, remaining:

(x - 1/3x) - 20

He ate half of remaining, remaining now:

(x - 1/3x) - 20 - 1/2((x - 1/3x) - 20)

Now, he has 25 left. So the previous equation is equal to 25. Then we solve for x:

[tex](x - \frac{1}{3}x) - 20 - \frac{1}{2}[(x - \frac{1}{3}x) - 20)]=25\\\frac{2}{3}x-20-\frac{1}{2}[\frac{2}{3}x-20]=25\\\frac{2}{3}x-20-\frac{1}{3}x+10=25\\\frac{1}{3}x=35\\x=\frac{35}{\frac{1}{3}}\\x=105[/tex]

The pack originally had 105 bars

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