Answer :
Answer:
e. Object X has traveled four times as far as object Y.
Explanation:
The distance covered by an object in uniform accelerated motion is given by:
[tex]d=ut+\frac{1}{2}at^2[/tex]
where
u is the initial velocity
t is the time
a is the acceleration
The two objects in the problem have same initial velocity, u = 0 (since they start from rest), so we can rewrite the equation as
[tex]d=\frac{1}{2}at^2[/tex]
We see that the distance covered is proportional to the square of the time. In this problem, the two objects X and Y have same acceleration, but object X accelerates for twice the time: since [tex]d \propto t^2[/tex], this means that the distance covered by X will be [tex]2^2 = 4[/tex] times higher that the distance covered by object Y.