Answer :
Answer:
0.57 seconds
Explanation:
If we just want to know how long it takes for the ball to hit the ground, it means only things happening in the vertical direction matter. The the horizontal velocity v and the 20m range of the ball don't matter for this question.
Given:
d = 1.6m
a = 9.8 m/s^2
vi = 0 m/s (this is the initial VERTICAL speed)
t = ?
d = vi * t + 0.5at^2
1.6 = 0 + 0.5(9.8)t^2
1.6 = 4.9t^2
t^2 = 0.33
t = 0.57
The time taken to hit the ground by the ball is required.
The time taken to hit the ground is 0.57 s.
v = Horizontal velocity
y = Height of table = 1.6 m
x = Displacement in x direction = 20 m
From the kinematic equations of projectile motion we have
[tex]y=\dfrac{1}{2}at^2\\\Rightarrow t=\sqrt{\dfrac{2y}{a}}\\\Rightarrow t=\sqrt{\dfrac{2\times 1.6}{9.81}}\\\Rightarrow t=0.57\ \text{s}[/tex]
The time taken to hit the ground is 0.57 s.
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