Answer :
Answer:
[tex]23.2 m/s^2[/tex]
Explanation:
First of all, we need to convert the angular velocity from revolutions per second to radiands per second. We know that
[tex]1 rev = 2 \pi rad[/tex]
So[tex]\omega = 2.9 rev/s \cdot 2\pi rad/rev =18.2 rad/s[/tex]
We also know that the distance of the inner ear from the centre of the circular path is
[tex]r = 7.0 cm = 0.07 m[/tex]
the radial (centripetal) acceleration experienced by a point on the inner ear is
[tex]a=\omega^2 r[/tex]
Therefore, substutiting the previous values, we find the radial acceleration of the endolymph fluid:
[tex]a=(18.2)^2(0.07)=23.2 m/s^2[/tex]