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Two blocks A and B with mA = 2.6 kg and mB = 0.81 kg are connected by a string of negligible mass. They rest on a frictionless horizontal surface. You pull on block A with a horizontal force of 6.5 N. Determine the tension in the string connecting the two blocks.

Answer :

Answer:

Explanation:

Given

Mass of block A [tex](m_a)[/tex]=2.6 kg

Mass of block B [tex](m_b)[/tex]=0.81 kg

Force of 6.5 N is applied on Block A

Force on Block A is F, Tension

thus

[tex]F-T=m_a\times a[/tex] -----1

where a=acceleration of the system

For Block B

[tex]T=m_b\times a[/tex] -----2

[tex]F=m_b\times a+m_a\times a[/tex]

[tex]F=\left ( m_a+m_b\right )a[/tex]

[tex]F=\left ( 2.6+0.81\right )a[/tex]

[tex]a=\frac{6.5}{3.41}[/tex]

[tex]a=1.96 m/s^2[/tex]

[tex]T=0.81\times 1.96=1.54 N[/tex]

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