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A basic cellular package costs $20 per month for 60 minutes of calling, with an additional charge of $0.20/min beyond that time. The cost formula would be C = 20 + 0.20(x − 60), where C is the cost measured in dollars and x is the number of calling minutes used. If you cannot have a bill greater than $60, what is the maximum number of calling minutes you can use?

Answer :

Answer: you can use 260 min, 60 min at a fixed price ($20) and extra 200.

Step-by-step explanation:

C(x) = 20 + 0.20(x − 60)

C(x) ≤ 60

20 + 0.20(x − 60) ≤ 60

0.20(x − 60) ≤ 60 - 20

0.20x - 12 ≤ 40

0.20x ≤ 40 + 12

0.20x ≤ 52

x ≤ 52/0.2

x ≤ 260

This way, you can use 260 min, 60 min at a fixed price ($20) and extra 200.

ashishdwivedilVT

The maximum number of calling minutes one can use is 260 minutes.

It is given that:

[tex]C = 20+0.20(x-60)[/tex]

Where C is the cost measured in dollars and x is the number of calling minutes used.

It is given that,

One cannot have a bill greater than $60.

i.e. [tex]C\leq 60[/tex]

What is inequality?

The relation between two expressions that are not equal.

[tex]20+0.20(x-60)\leq 60\\\\0.20(x-60) \leq 40\\\\x-60 \leq 200\\\\x\leq 260[/tex]

Therefore, the maximum number of calling minutes you can use is 260 minutes.

To get more about inequality visit:

https://brainly.com/question/11613554

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