Answer:
the answer is C, 7
Step-by-step explanation:
it is 7 because 2 doesnt go into 5 evenly so you would have to buy 2 packs of black pens (which would equal 10 black pens)
and then to get 10 blue pens you would have to buy 5 packs because 2x5=10 so 5 blue packs plus 2 black packs (2+5) = 7
your welcome.
Option (C)
Answer:
The fewest total number of packages you can buy to have equal numbers of blue and black pens is 7
Solution:
Given that blue pens comes in packages of 2 and black pens come in package of 5.
We need to evaluate fewest total number of packages, so that we can have equal number of blue and black pens.
1 pack of blue pen = [tex]1 \times 2[/tex] = 2 blue pens
2 pack of blue pen = [tex]2 \times 2[/tex] = 4 blue pens
3 pack of blue pen = [tex]3 \times 2[/tex] = 6 blue pens
4 pack of blue pen = [tex]4 \times 2[/tex] = 8 blue pens
5 pack of blue pen = [tex]5 \times 2[/tex] = 10 blue pens
Now let’s look on data of black pen,
1 pack of black pen = [tex]5 \times 1[/tex] = 5 black pens
2 pack of black pen =[tex]5 \times 2[/tex] = 10 black pens
So from above data, we can say that 5 pack of blue pens and 2 packs of black pens will have 10 blue pens and 10 black pens.
So total number of packages = 5 pack of blue pen + 2 pack of black pen
= 7 packs
Hence we need to buy at least 7 packages, 5 of blue pens and 2 of black pens so that we can have equal number of blue and black pens. Hence option (C) is correct.
