Answer :
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➷ Let the width be 'x' and the length be 'x + 2'
Area = l x w
Substitute the values in:
48 = x(x + 2)
48 = x^2 + 2x
Use trial and error [it'll only take a few turns] to get the value for x
x = 6
x + 2 = 8
Thus, the length of the paddock is 8m and the width is 6m.
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ANSWER:
The length and width of the paddock are 8, 6.
SOLUTION:
Given, length of a paddock is 2m more than its width.
Let the length of paddock be “x”
Then the width of paddock becomes x – 2.
Also given that, area of paddock is 48 [tex]\mathrm{m}^{2}[/tex]
area = 48
In general, paddocks are rectangular in shape. Area of rectangle is given by
area of rectangle = length [tex]\times[/tex] breadth
Length [tex]\times[/tex] breadth = 48
x(x – 2) = 48
we can write 48 as product of 8 and 6
x(x – 2) = 8 x 6
Now, by comparing on both sides, We can say that
x = 8 and x -2 = 6
Finally , the value of x is 8 and x - 2 is 6
Hence, the length and width of the paddock are 8, 6.