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Car B is following Car A and has a greater speed than Car A. the two cars are moving in a straight line and in the same direction, and have the same mass. in situation one, Car A is traveling at 10 mph and car B at 20 mph. in situation 2, car A is traveling at 30 mph and car B at 40 mph. assuming a perfectly inelastic collision in which the cars stick together after the collision, what will be true?

Answer :

Answer:

Collision force will be same in both the cases.

Explanation:

A perfectly inelastic collision is said to take place  when a system loses the amount of its Kinetic Energy at its maximum. In a perfectly inelastic collision,  the colliding particles stick to each other. In such a collision, kinetic energy is lost by combining the two bodies with each other.

In situation 1:

Speed of Car A, [tex]v_{A} = 10 mph[/tex]

Speed of Car B, [tex]v_{B} = 20 mph[/tex]

Relative speed of car A and car B, [tex]v = v_{b} - v_{a} = 10 m/s[/tex]

Now, in the situation 2:

Speed of car A, [tex]v_{A} = 30 mph[/tex]

Speed of car B, [tex]v_{B} = 40 mph[/tex]

Relative speed of car A and car B, [tex]v = v_{b} - v_{a} = 10 m/s[/tex]

Therefore, Car A and Car B both have the same relative speed, v = 10 m/s

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