Answer :
Answer:
[tex]1.25 m/s^2[/tex]
Explanation:
The acceleration of gravity at the surface of a planet planet is given by:
[tex]g=\frac{GM}{R^2}[/tex]
where
G is the gravitational constant
M is the mass of the planet
R is the radius of the planet
Calling M the Earth's mass and R the Earth's radius, the equation above represents the acceleration due to gravity at the Earth's surface, and so
[tex]g=10 m/s^2[/tex]
Here we have a planet with:
M' = M/2 (mass is half that of Earth)
R' = 2R (radius is twice that of Earth)
So the acceleration due to gravity of this planet is:
[tex]g'=\frac{GM'}{R'^2}=\frac{G(M/2)}{(2R)^2}=\frac{1}{8}(\frac{GM}{R^2})=\frac{g}{8}=\frac{10}{8}=1.25 m/s^2[/tex]