Answer :
Answer: The largest dimensions that are possible would be 50 foot by 125 foot.
Step-by-step explanation:
Since we have given that
Amount a farmer has available = $1500
Let x be the side perpendicular to the river.
Let y be the side parallel to the river.
Number of section perpendicular to the river = 3
cost of material for the side parallel to the river = $6 per foot
Cost of material for the side perpendicular to the river = $5 per foot
So, total cost becomes
[tex]Cost=6y+5(3x)=1500\\\\Cost=6y+15x=1500\\\\y=\dfrac{1500-15x}{6}}[/tex]
Area would be
[tex]A=x\times y\\\\A=x(\dfrac{1500-15x}{6})\\\\A=\dfrac{1}{6}(1500x-15x^2)\\\\A'=\dfrac{1}{6}(1500-30x)[/tex]
Now, put A' = 0 to get the critical points.
So, it becomes,
[tex]\dfrac{1}{6}(1500-30x)=0\\\\1500-30x=0\\\\1500=30x\\\\x=\dfrac{1500}{30}\\\\x=50[/tex]
[tex]A''=\dfrac{-30}{6}=-5<0[/tex]
so, at x= 50 it will give maximum dimensions.
[tex]y=\dfrac{1500-15x}{6}=\dfrac{1500-15\times 50}{6}=\dfrac{750}{6}=125[/tex]
So, the largest dimensions that are possible would be 50 foot by 125 foot.