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A boy shoves his stuffed toy zebra down a frictionless chute. It starts at a height of 1.81 m above the bottom of the chute with an initial speed of 1.89 m/s . The toy animal emerges horizontally from the bottom of the chute and continues sliding along a horizontal surface with a coefficient of kinetic friction of 0.269 . How far from the bottom of the chute does the toy zebra come to rest? Assume ????=9.81 m/s2 .

Answer :

Chenk13

Answer:

7.4 m

Explanation:

Friction is going to consume all of the initial energy:

[tex]\frac{1}{2}m\ddot{x}^2+mgy=F_{friction}x=\mu mgx[/tex]

Solving for x:

[tex]x=\frac{\ddot{x}^2}{2\mu g}+\frac{y}{\mu}[/tex]

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