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A ball is thrown straight up and reaches a maximum height of 5 m.
a) What is the initial velocity of the ball?

Answer :

MathPhys

Answer:

9.9 m/s

Explanation:

Given:

Δy = 5 m

v = 0 m/s

a = -9.8 m/s²

Find: v₀

v² = v₀² + 2aΔy

(0 m/s)² = v₀² + 2 (-9.8 m/s²) (5 m)

v₀ = 9.9 m/s

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