At what value of x does graph of the following function f(x) have a vertical asymptote? F(x)= 1/x+3

Answer:
A
Step-by-step explanation:
Given
f(x) = [tex]\frac{1}{x+3}[/tex]
The denominator of f(x) cannot be zero as this would make f(x) undefined.
Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.
x + 3 = 0 → x = - 3 is the vertical asymptote
The correct answer is A. -3
Vertical asymptotes occur when the denominator of a rational expression does not cancel the numerator.
To find the vertical asymptote we should equate the denomiantor to 0
So, according to the euation,
x + 3 = 0
⇒ x= -3
So, at x = -3 the function will have a vertical asymptote.
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