Answer :
Answer:
the spring is compressed by x = 2.45 cm
Explanation:
As we know that at the bottom of the bounce the net force on the child is given as
[tex]F_s - mg = ma[/tex]
here we know that
[tex]F_s = kx[/tex]
now we will have
[tex]kx - mg = ma[/tex]
[tex](2.0 \times 10^4) x = m( g + a)[/tex]
[tex](2 \times 10^4) x = 25(9.8 + 9.8)[/tex]
[tex]x = 0.0245 m[/tex]
so the spring is compressed by x = 2.45 cm