Answer :
Answer:
The percent chloride in the sample is 1.56%
Step-by-step explanation:
Hi there!
The molecular formula of silver chloride is AgCl. Its molar mass (the mass of a mol of AgCl) is 143.32 g/mol. Then the number of moles of AgCl obtained in the precipitated will be:
1.58 g · (1 mol/143.32 g) = 0.0110 mol
Then, since 1 mol AgCl contains 1 mol Cl⁻ (chloride), in the sample of compost there will be 0.0110 mol Cl⁻.
The mass of 0.0110 mol Cl⁻ is:
0.0110 mol Cl⁻ · (35.453 g /mol) = 0.390 g Chloride.
Then, the percent chloride in the sample will be:
0.390 g · (100 % / 25.0 g) = 1.56%
The percent chloride in the sample is 1.56%