Answered

The area of the base of a cone is 16, and the height is 10. Find the area of a cross-section that is distance 5 from the vertex.

Answer :

Answer: Area of cross section would be 4 square units.

Step-by-step explanation:

Since we have given that

Area of base of cone = 16 sq. units

Height = 10

We need to find the area of cross section that is distance 5 from the vertex.

So, Height of cross section = 5 units

total height of cone = 10

It means the cross section is half of the whole cone.

So, it becomes,

[tex](\dfrac{1}{2})^2=\dfrac{A}{16}\\\\\dfrac{1}{4}=\dfrac{A}{16}\\\\16=4A\\\\\dfrac{16}{4}=A\\\\4=A[/tex]

Hence, Area of cross section would be 4 square units.

Answer:

4 square units

Step-by-step explanation:

5/10=0.5

(0.5)^=0.25

16*0.25=4

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