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A pizza shop offers ten toppings.
How many different "three-topping-pizzas"
can be formed with the ten toppings?
Assume no topping is used twice.​

Answer :

hannyboo212

Answer:

120

Step-by-step explanation:

120 different "three-topping-pizzas" can be formed with the ten toppings.

What is a combinaton?

A combination is a way of selecting items from a collection where the order of selection does not matter.

Mathematically, nCr = n!/r!(n-r)!

where, n represents the total number of items

and r represents number of items chosen at a time.

Now,the total number of toppings given,n = 10

Number of toppings chosen,r = 3

So, the number of different three-toppings can be formed,

nCr = n!/r!(n-r)!

nCr = 10!/3!(10-3)!

nCr = 10!/3!7!

nCr =10x9x8/3x2x1

nCr = 120

Therefore, 120 different "three-topping-pizzas" can be formed with the ten toppings.

More about combinations :

https://brainly.com/question/8044761

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