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The prism has a surface area of 1312 mm2.

What would the surface area of the prism be if each dimension were halved?


mm2

Prism with a length of thirty-two millimeters, a width of ten millimeters, and a height eight millimeters

Answer :

TSO
Surface Area = 2(lw + lh + wh)

Divide each dimension by half, and then plug it in to the formula.

32/2 = 18
10/2 = 5
8/2 = 4

Surface Area = 2((4)(5) + (4)(18) + (5)(18))
SA = 2(20 + 72 + 90)
SA = 2(182)

SA = 364

The surface area if each dimension was halved would be 364 mm^2.

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