Answer :
Answer:0.0668
Step-by-step explanation:
As per given we have,
[tex]\mu=70[/tex] [tex]\sigma= 2[/tex]
Also, the distribution is approximately normal in shape.
since , [tex]z=\dfrac{x-\mu}{\sigma}[/tex]
z-score corresponds to x= 73 will be :_
[tex]z=\dfrac{73-70}{2}=1.5[/tex]
P-value = [tex]P(x\geq73)=P(z\geq1.5)[/tex]
[tex]=1-P(z<1.5)=1-0.9331927=0.0668073\approx0.0668[/tex]
Hence, the probability that this student is 73 inches (6'1") or taller = 0.0668