a) [tex]3.38 m/s^2[/tex]
The acceleration of the aircraft can be found by using Newton's second law:
[tex]F=ma[/tex]
where
F is the net force on the aircraft
m is the aircraft's mass
a is the acceleration
In this problem, we have
m = 350 kg
F = 1184 N
Re-arranging the equation for a, we find the acceleration of the plane:
[tex]a=\frac{F}{m}=\frac{1184}{350}=3.38 m/s^2[/tex]
b) 33.8 m/s
Since the motion of the aircraft is a uniform accelerated motion, we can use the following suvat equation
[tex]v=u+at[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the aircraft in the problem,
u = 0 (it starts from rest)
[tex]a=3.38 m/s^2[/tex] is the acceleration
Therefore, the velocity after t = 10 s is
[tex]v=0+(3.38)(10)=33.8 m/s[/tex]
