What is the equation of the line described below written in slope-intercept form? the line passing through point (2, 4), parallel to the line whose equation is y = x y = -x y = x + 2 y = -x + 2

Answer :

carlosego

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

[tex]y = mx + b[/tex]

Where:

m: It's the slope

b: It is the cut-off point with the y axis

By definition, if two lines are parallel then their slopes are equal.

If we have the following line:

[tex]y = x[/tex]

Whose slope is [tex]m_ {1} = 1[/tex]

So, a line parallel to it has a slope [tex]m_ {2} = 1[/tex]

Therefore, the equation is of the form:

[tex]y = x + b[/tex]

If the line passes through point [tex](2,4),[/tex] we can substitute in the equation and find "b":

[tex]4 = 2 + b\\4-2 = b\\b = 2[/tex]

Finally, the equation is:

[tex]y = x + 2[/tex]

ANswer:

[tex]y = x + 2[/tex]

Answer:

y=x+2

Step-by-step explanation:

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