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How many moles of a gas sample are in a 10.0 L container at 373 K and 203 kPa ?


0.33 mole

0.66 mole

1.11 moles


3.05 moles


0.66 mole is correct

Answer :

Answer:

The number of moles = 0.66  mole

Explanation:

Given as :

The volume of container (V) = 10.0 liter

The temperature (T)= 373 kelvin

The pressure of gas (P) = 203 k pa = 2.0034 atm

Let the number of mole = n

Now from at ideal gas law

PV = nRT

Where R = 0.08206 L atm per mol per kelvin

SO, (2.0034 × 10 ) = n × 0.08206 × 373

Or, (20.034 ) = n × 30.608

∴ n = [tex]\frac{20.034 \times 10^{4}}{30.608}[/tex]

Or n = 0.654

Hence the number of mole  =  0.66 mole  Answer  

Answer:

0.66

Explanation:

I took the test

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