Answer :
Answer :
(1) The number of valence electrons present in the compound is, 20
(2) The number of bonded electrons present in the compound is, 16
(3) The number of lone pair electrons present in the compound is, 4
(4) The number of single bonds present in the compound is, 8
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
The given molecule is, [tex]CH_3CH_2OH[/tex]
As we know that carbon has '4' valence electrons, hydrogen has '1' valence electrons and oxygen has '6' valence electrons.
Therefore, the total number of valence electrons in [tex]CH_3CH_2OH[/tex] = 2(4) + 6(1) + 6 = 20
According to Lewis-dot structure, there are 16 number of bonding electrons and 4 number of non-bonding electrons or lone pair of electrons.
The Lewis-dot structure of [tex]CH_3CH_2OH[/tex] is shown below.
In the Lewis structure of ethanol, there are 4 lone pair of electrons, 8 single bonds, bonded electrons are 16 .
For Lewis structure of ethanol, find the attachment
The ethanol's formula,
[tex]\rm\bold { CH_3CH_2OH}[/tex]
As we know
C- 4 valence electron
H-1
O - 6
The number of valence electron in molecule will be 20
In Lewis structure we can see that
- The number of bonded electrons present in the compound is, 16 .
- The number of lone pair electrons present in the compound is, 4 .
- The number of single bonds present in the compound is, 8
So we can conclude that in the Lewis structure of ethanol, there are 4 lone pair of electrons, 8 single bonds, bonded electrons are 16 .
To know more about Lewis structure, refer to the link:
https://brainly.com/question/20300458?referrer=searchResults
