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A time-varying horizontal force F(t) = At 4 + Bt 2 acts for 0.500 s on a 12.25-kg object, starting at time t = 1.00 s. In the SI system, A has the numerical value 4.50 and B has the numerical value 8.75. (a) What are the SI units of A and B? Enter your answers separated by a c.

Answer :

lublana

Answer:

S.I unit  of

[tex]A=Ns^{-4}[/tex]

and [tex]B=Ns^{-2}[/tex]

Explanation:

We are given that a time varying horizontal force

[tex]F(t)=At^4+Bt^2[/tex]

Mass of object =12.25 kg

Initial time , t=1.00 s

Time for which force act on object=0. 500 s

In S. I unit

Numerical value of A=4.50

Numerical value  of B=8.75

We have to find the S. I units of A and B.

We know that S.I unit if force is Newton.

When S.I unit of force is Newton  and time in seconds then S. I units of each term in given force must be equal to Newton.Because when S.I unit of sum is Newton then it is necessary that S.I unit of each term of sum should be equal to newton.

[tex]A(s)^4=N[/tex]

S.I unit of A is given by

[tex]A=N/s^4[/tex]

[tex]B(s)^2=N[/tex]

S.I unit of B is given by

[tex]B=N/s^2[/tex]

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