Given that Young's modulus is a quantitative measure of stiffness of an elastic material. Suppose that for aluminum alloy sheets of a particular type, its mean value and standard deviation are 70 GPa and 1.6 GPa, respectively.

a.If X is the sample mean Young's modulus for a random sample of n = 16 sheets, the sampling distribution of X centered at 70 GPa, and the standard deviation of the X distribution is given by

b. If X is the sample mean Young's modulus for a random sample of n = 64 sheets, the sampling distribution of X centered at 70 GPa, and the standard deviation of the X distribution is given by

Answer :

Answer:

a) [tex]\sigma = 0.4[/tex]

b) [tex]\sigma = 0.2[/tex]

Step-by-step explanation:

The standard deviation of the sample is the standard deviation of population divided by the square root of the length of the sample.

In this problem, we have that:

Suppose that for aluminum alloy sheets of a particular type, its mean value and standard deviation are 70 GPa and 1.6 GPa, respectively. This means that [tex]\sigma = 1.6[/tex].

a.If X is the sample mean Young's modulus for a random sample of n = 16 sheets, the sampling distribution of X centered at 70 GPa, and the standard deviation of the X distribution is given by

[tex]s = \frac{\sigma}{\sqrt{16}} = \frac{1.6}{4} = 0.4[/tex]

b. If X is the sample mean Young's modulus for a random sample of n = 64 sheets, the sampling distribution of X centered at 70 GPa, and the standard deviation of the X distribution is given by

[tex]s = \frac{\sigma}{\sqrt{64}} = \frac{1.6}{8} = 0.2[/tex]

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