Answer:
Explanation:
We should start first with a(t), then plot v(t) and h(t)
a = g = -9.81 m/s2 is exerted by gravitational acceleration and constant no matter what t is. Since we are plotting only the magnitude, we can expect a straight horizontal line at 9.81.
[tex] v(t) = v_0 + at = v_0 - 9.81t[/tex]
Since the ball start from rest, [tex]v_0 = 0 m/s[/tex]
[tex]v(t) = -9.81t[/tex]
v(t) would start out negative, then increasing negatively in magnitude, as soon as the ball hit the floor and rebounds, expect the v jumps to positive value immediately after, then decrease in magnitude until 0 where it gets to maximum height.
The plot of v magnitude should be v-shaped.
As for height:
[tex]h(t) = h_0 + vt + at^2/2[/tex]
[tex]h(t) = h_0 + vt - 4.9t^2[/tex]
Since this is a quadratic equation, we can expect the plot to be parabolic-shaped.
Picture of graph is attached
