Answer :
Explanation:
Given that,
Distance covered by the skier, d = 62.5 m
Slope from the horizontal, [tex]\theta=25^{\circ}[/tex]
Let v is the final speed of the skier. Using the third equation of kinematics as :
[tex]v^2=u^2+2ad[/tex]
Here, [tex]a=g\ sin\theta[/tex] and u = 0
[tex]v^2=2g\ sin\thetad[/tex]
[tex]v=\sqrt{2g\ sin\theta d}[/tex]
[tex]v=\sqrt{2\times 9.8\times \ sin(25)\times 62.5}[/tex]
v = 22.75 m/s
The final speed of a skier is 22.75 m/s.
Let t is the time taken. Using the first equation of motion as :
[tex]t=\dfrac{v-u}{g\ sin\theta}[/tex]
[tex]t=\dfrac{22.75}{9.8\times \ sin(25)}[/tex]
t = 5.49 seconds
Hence, this is the required solution.