Answer :
Answer:option D= 82.6°C
Explanation:
Step 1: determine the molality
Molality = moles of solute/ kg of solvent.
(Recall: number of moles= mass / molar mass).
Therefore, 375/256.5 g/mol = 1.4620 mole.
Substituting into the molality equation we have,
1.4620/ 0.1250kg = 11.696.
∆T(b) = k(b) × molality
∆T(b) = 82.6°C
The boiling point of a solution prepared by dissolving 375 g of sulfur is 82.6°C.
What is Boiling point?
This is the temperature in which a liquid starts changing to steam or vapor.
Molality = moles of solute/ mass(kg) of solvent.
Number of moles = mass / molar mass.
= 375g /256.5 g/mol
= 1.4620 mol.
Substitute the value of number of mole into the molality equation:
1.4620 mol/ 0.1250kg
= 11.696 mol/kg
∆T(b) = k(b) × molality
= 7.05 × 11.696
= 82.6°C
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