Carbon tetrachloride, once widely used in fire extinguishers andas a dry cleaning fluid, has been found to cause liver damage tothose exposed to its vapors over long periods of time. What is theboiling point of a solution prepared by dissolving 375 g of sulfur(S8, MW = 256.5g/mol) in 1250 g of CCl4?Kb = 5.05°C/m, boiling point ofpure CCl4 = 76.7°C)?A.70.8°C B.75.2°CC.78.2°CD.82.6°CE.>85°C

Answer :

codedmog101

Answer:option D= 82.6°C

Explanation:

Step 1: determine the molality

Molality = moles of solute/ kg of solvent.

(Recall: number of moles= mass / molar mass).

Therefore, 375/256.5 g/mol = 1.4620 mole.

Substituting into the molality equation we have,

1.4620/ 0.1250kg = 11.696.

∆T(b) = k(b) × molality

∆T(b) = 82.6°C

The boiling point of a solution prepared by dissolving 375 g of sulfur is 82.6°C.

What is Boiling point?

This is the temperature in which a liquid starts changing to steam or vapor.

Molality = moles of solute/ mass(kg) of solvent.

Number of moles = mass / molar mass.

                             = 375g /256.5 g/mol

                             = 1.4620 mol.

Substitute the value of number of mole into the molality equation:

1.4620 mol/ 0.1250kg

= 11.696 mol/kg

∆T(b) = k(b) × molality

         =   7.05 × 11.696

       = 82.6°C

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