Answer :
Answer:
a. 0.83
b. 0.97
c.$14500 or more
d. stay with bid in part c
e. $4400.00
Step-by-step explanation:
a. the probability that the bid of $12, 000 is accepted=
probability = bid/ Max bid = $12000/ $14500 =0.83
b. the probability that the bid of $14, 000 is accepted=
probability = bid/ Max bid = $14000/ $14500 =0.97
c. the maximum bidder get the property, since the bid is in the range of $10100 and $14500, therefore, the bidder with $14500 or more will get the property.
d. if your objective is to maximize expected profit, stay with your bid in part c. which is $14500 or more will get the property.
e. the expected profit will be $14500 -$10100 = $4,400.00
Based on the variable being uniformly distributed, the Probability of $12,000 bid being accepted is 43.2%.
The probability of $14,000 bid being accepted is 88.6%.
The amount you should bid is $14,500.
The expected profit for the bid is is $1,972.
What is the probability that the bid of $12,000 is accepted?
= (Bid - lower range of uniform distribution) / (Upper range - Lower range)
= (12,000 - 10,100) / (14,500 - 10,100)
= 43.2%
What is the probability that the bid of $14,000 is accepted?
= (14,000 - 10,100) / (14,500 - 10,100)
= 88.6%
What amount should you bid to maximize your chances?
The amount you should bid that would maximize your chances should be the highest possible bid of $14,500.
What is the expected profit at this bid?
If you bid $13,100 and the person pays you $16,000, your profit would be:
= 16,000 - 13,100
= $2,900
The expected profit is therefore:
= Profit x Probability of winning by bidding 13,100
= 2,900 x ((13,100 - 10,100) / (14,500 - 10,100))
= 2,900 x 0.68
= $1,972
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