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The Jacksons are planning their next family night. They always have dinner out somewhere and then do something fun together. There are 2 adults and 6 children in
the family. Each family member is allowed 2 meal suggestions, and each child is allowed 2 activity suggestions. Assuming no family members choose the same thing,
how many different family night possibilities are there?​

Answer :

morganwags0609

Answer:

Step-by-step explanation:

First you do 2 meals times 2 adults which get 4 then take 2 meals per child and take 6 children times 2 meals you would get 12 so you take 12 plus 4 and get 16

fichoh

Using the arithmetic operations, the total number of different family night possibilities is 28.

Given the Parameters :

  • Number of children = 6
  • Number of adults = 2

  • Suggestion per adult = 2
  • Suggestion per child = 2

  • Total number of family member = (6 + 2) = 8

Total meal suggestion :

  • Total family member × 2

8 × 2 = 16

Total activity suggestion :

  • Total number of children × 2

6 × 2 = 12

Number of different possibilities :

  • 12 + 16 = 28 different activities

Hence, there are 28 different activities possible.

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