Answer :
Answer:
[tex]T_{P}=(2.6667)(10^{-3})h[/tex]
Explanation:
Let's write the equation of the production rate for the assembly machine :
[tex]T_{P}=T_{C}+(n).(m).(p).(T_{D})[/tex]
Where [tex]T_{P}[/tex] is the production rate for the assembly machine.
Where [tex]T_{C}[/tex] is the ideal cycle time
Where n is the number of stations.
Where m is the number stations that get jam when the defect occurs.
Where p is the defect rate at each station.
And where [tex]T_{D}[/tex] is the average downtime per breakdown
We are looking for the hourly production rate ⇒
[tex]1h=60min\\1min=60s[/tex] ⇒
[tex]1h=3600s[/tex] ⇒
[tex]6s=\frac{(6s)(1h)}{(3600s)}= \frac{1}{600}h[/tex]
[tex]60min=1h[/tex] ⇒
[tex]1.2min=\frac{(1.2min)(1h)}{(60min)}=0.02h[/tex]
[tex]T_{P}=\frac{1}{600}h+(10)(1.0)(0.005)(0.02h)=\frac{1}{375}h=(2.6667)(10^{-3})h[/tex]
m = 1.0 in the equation.