Answer :
Answer:
The horizontal component of the force is 48 N.
Step-by-step explanation:
The angle that the rope makes with with the horizontal is 15°, that means, the horizontal component of the force [tex]F_H[/tex] is
[tex]cos(15^o)=\frac{F_H}{50N}[/tex]
[tex]\boxed{ F_H=50N*cos(15^o)=48N}[/tex]
