SOLUTION:
[tex]Point \ (1,3)[/tex]
Let's use the following System of Linear Equations in Two Variables in order to solve this exercise:
[tex]\begin{array}{c}(1)\\(2)\end{array}\left\{ \begin{array}{c}y=2x+1\\y=-4x+7\end{array}\right.[/tex]
So we can graph these lines using two points.
For eq (1):
[tex]y=2x+1 \\ \\ If \ x=0 \ then \ y=2(0)+1 \therefore y=1 \\ \\ If \ y=0 \ then \ 0=2x+1 \therefore x=-\frac{1}{2} \\ \\ \\ Points: \\ \\ (0,1) \\ \\ (-\frac{1}{2},0)[/tex]
So graph a line that passes through these two points. This is the red line shown below.
For eq (2):
[tex]y=-4x+7 \\ \\ If \ x=0 \ then \ y=-4(0)+7 \therefore y=7 \\ \\ If \ y=0 \ then \ 0=-4x+7 \therefore x=\frac{7}{4} \\ \\ \\ Points: \\ \\ (0,7) \\ \\ (\frac{7}{4},0)[/tex]
So graph a line that passes through these two points. This is the blue line shown below.
The solution of this system of equation is the point of intersection, which is (1,3)
Parallel lines: https://brainly.com/question/12169569
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Answer:
Point (1,3)
Step-by-step explanation:
The main idea of a system is: system of linear equations has 2 or more linear equations. The solution to a system in two ordered pairs that make the equation true. Or in this case, where they intersect.
If you look at the graph, the points intersect at (1,3) therefore, your answer is point (1,3)
hope this helped!! :-))
