Answer :
Answer:
Force of friction is 10 N.
Explanation:
Given:
Mass of the table is, [tex]m=4\textrm{ kg}[/tex]
Force acting towards right, [tex]F=50\textrm{ N}[/tex]
Net acceleration of the table, [tex]a=10\textrm{ }m/s^{2}[/tex]
Let the force of friction acting on the table to the left be [tex]f[/tex] N.
Therefore, net force acting on the table is given as,
[tex]F_{net}=F-f=50-f[/tex]
Now, as per Newton's second law of motion,
[tex]F_{net}=ma[/tex]
Equating the above two equations, we get
[tex]50-f=ma\\f=50-ma\\f=50-(4\times 10)\\f=50-40=10\textrm{ N}[/tex]
Therefore, the magnitude of the force of friction acting on the table is 10 N to the left direction.