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Playing shortstop, you pick up a ball and throw it to second base. The ball is thrown horizontally, with a speed of 21m/s, directly towards point A. When the ball reaches the second baseman 0.46 s later, it is caught at point B. Part A.) how far were you from the second baseman? Part B.) What is the distance of vertical drop, from A to B

Answer :

Hania12

Answer:

distance to second baseman = 9.66 m

vertical drop = 1.058m

Explanation:

A) applying motion equation to horizontal motion

(assuming no acceleration in horizontal motion)

distance to second baseman = velocity * time

                                                = 21 * 0.46

                                                = 9.66 m

B) applying motion equation to vertical motion

(starting velocity was horizontal. therefore no vertical component. subjected to gravity ,g=10m/s2)

[tex]s=ut+\frac{1}{2} *at^{2} \\=0+\frac{1}{2}*10*0.46^{2}  \\=1.058 m[/tex]

vertical drop = 1.058m

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