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What is the equation, in point-slope form, of the line that is
perpendicular to the given line and passes through the
point (-4, -3)?
y + 3 = -4(x + 4)
y + 3 = 7 (x+4)
y + 3 = 7/(x + 4)
y + 3 = 4(x + 4)

What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (-4, -3)? y + 3 = -4(x + 4) y + 3 = class=

Answer :

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Answer:

[tex] y+3=\frac{1}{4}(x+4)[/tex]

Step-by-step explanation:

The slope of given line is:

[tex] \text{Slope}=\frac{1-(-3)}{-1-0}=-4\\

\text{Let slope of perpendicular line be= m}\\

\implies m\times (-4)=(-1)\implies m=\frac{1}{4}\\

\text{Thus the required equation:}\\

(y-(-3))=\frac{1}{4}(x-(-4))\\

(y+3)=\frac{1}{4}(x+4)\\[/tex]

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