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In a factory A, about 3 out of every 2,000 toys have a defect. In factory B, about 5 out of every 4,500 toys have a defect. One week, each factory produced 18,000 toys. Which factory had the greater number of toys with defects? Solve. Use a proportion to solve.

Answer :

zeidanramsey

Answer:

27

Step-by-step explanation:

Factory A proportion:

3 : 2,000

Factory B proportion:

5 : 4,500 (this can be simplified):

1 : 900

Now plug in 18,000 to each proportion:

Factory A:

x : 18,000

3 : 2,000

x = 27

Factory B:

x : 18,000

1 : 900

x = 20

Factory A had the greater amount of defects, 27

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