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Laura is planning a party for her son. She has $50 dollars remaining in her budget and wants to provide one party favor per person to at least 10
guests. She found some miniature stuffed animals for $6.00 each and some toy trucks for $4.00 each.
Which system of inequalities represents this situation, where x is the number of stuffed animals and y is the number of toy trucks?

Answer :

Answer:

6x + 4y ≤ 50

x + y ≥ 10

Step-by-step explanation:

$6 is the cost of stuffed animals $4 is the cost of toy trucks and the her maximum budget is $50 it would be 6x+4y is less then or equal to 50 and there is AT LEAST 10 people so the amounts which are x and y would be equal to or greater than 10.

Answer:

[tex]6x+4y\leq 50[/tex]

[tex]x+y\geq 10[/tex]

Step-by-step explanation:

[tex]x[/tex] represents the number of stuffed animals.

[tex]y[/tex] represents the number of toy trucks.

Now, according to the problem, she found stuffed animals for $6.00 each and toy trucks for $4.00 each. Also, Laura has a restricted budget of $50. All these can be expressde as

[tex]6x+4y\leq 50[/tex]

Also, the problem states that Laura wants to provide one partu favor per person to at least 10 people, that means

[tex]x+y\geq 10[/tex], because "at least" represents a minimum value, which is expressed with [tex]\geq[/tex].

Therefore, the inequality system that models this situation is

[tex]6x+4y\leq 50[/tex]

[tex]x+y\geq 10[/tex]

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