Answer :
Answer:
[tex]\frac{816}{7}\ g[/tex]
Step-by-step explanation:
Let
x -----> the grams of zinc
y -----> the grams of copper
we know that
[tex]\frac{x}{y}=\frac{3}{14}[/tex] -----> equation A
we have
[tex]y=544\ g[/tex]
substitute the value of y in the equation A
[tex]\frac{x}{544}=\frac{3}{14}[/tex]
solve for x
[tex]x=\frac{3}{14}(544)[/tex]
[tex]x=\frac{1,632}{14}\ g[/tex]
simplify
[tex]x=\frac{816}{7}\ g[/tex]