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What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?

A. y+7=-2/3(x-1)
B. y+7=2/3(x+1)
C. y-7=-2/3(x+1)
D. y-7=2/3(x-1)

Answer :

bayosanuade

Answer: y + 7 = -2/3 (x - 1 )

Step-by-step explanation:

The equation of a line in point - slope form is given as :

[tex]y-y_{1}[/tex] = m([tex]x-x_{1}[/tex] )

Where m is the slope and ([tex]x_{1}[/tex] , [tex]y_{1}[/tex]) is the given point

substituting the values into the formula , we have:

y - (-7) = -2/3 ( x - 1)

y + 7 = -2/3(x - 1 )

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