To solve this problem it is necessary to use the concepts related to pressure. The pressure can be defined as
[tex]P = \frac{F}{A}[/tex]
Due to the continuity and pressure conservation relationship, the pressure must be preserved to support the weight (gravity) and to lift it (lift)
In this way,
[tex]P_g = P_l[/tex]
[tex]\frac{F_g}{A} = \frac{F_l}{a}[/tex]
That is equal to
[tex]\frac{F_g}{F_l}=\frac{A}{a}[/tex]
We have a ratio of A/a = 10, then
[tex]\frac{F_g}{F_l} = 10[/tex]
[tex]\frac{mg}{F_l} = 10[/tex]
[tex]\frac{mg}{10} = F_l[/tex]
[tex]F_l = \frac{(15)(9.81)}{10}[/tex]
[tex]F_l = 147.15N[/tex]
Therefore the force required to do the lifting is 147.15N
