Answer :
Answer:
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Step-by-step explanation:
Consider the provided information,
Let X is the number of defective bulbs.
Ten light bulbs are randomly selected.
The likelihood that a light bulb is defective is 5%.
Therefore sample size is = n = 10
Probability of a defective bulb = p = 0.05.
Therefore, q = 1 - p = 1 - 0.05 = 0.95
Mean of binomial random variable: [tex]\mu=np[/tex]
Therefore, [tex]\mu=10(0.05)=0.5[/tex]
Variance of binomial random variable: [tex]\sigma^2=npq[/tex]
Therefore, [tex]\sigma^2=10(0.05)(0.95)=0.475[/tex]
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.