Answer :
Answer:
Step-by-step explanation:
Let [tex]x_m[/tex] and [tex]x_w[/tex] be the production level of milk and white chocolate-covered strawberries respectively. According to the given data, we know the total profit will be
[tex]P(x_m,x_w)=$2.25x_m+$2.50x_w[/tex]
The restrictions can be written as
[tex]x_m+x_w \leq 800[/tex]
[tex]x_w\leq x_m/2[/tex]
[tex]x_w\leq 200[/tex]
All the restrictions can be plotted in the same graph to find the feasible region where all of them are met. The graph is shown in the image below
The optimal solution will be the level of production such that
* All restrictions are met
* The total profit is maximum
The optimal level of production can be found in (at least) one of the vertices of the feasible region. We'll try each one as follows
P(0,0)=0
P(400,200)=$2.25 (400)+$2.50 (200) = $1400
P(600,200)=$2.25 (600)+$2.50 (200) = $1850
P(800,0)=$2.25 (800)+$2.50 (0) = $1800
We must produce 600 milk chocolate-covered strawberries and 200 white chocolate-covered strawberries to have a maximum profit of $1850/month

Answer:
The total profit per month is [tex]$\$ 1850$[/tex].
Explanation:
There are two types of chocolates that can be produced milk chocolate and strawberry covered chocolate.
To find the profit we make following equation, [tex]$\mathrm{P}=\$ 2.25 \mathrm{SC}+\$ 2.50 \mathrm{WC}$[/tex]
where is strawberry chocolate and WC is White milk chocolate.
The maximum production level can be [tex]800[/tex] boxes per month and white chocolates can not exceed the [tex]200[/tex] boxes per month
So we assume making [tex]600[/tex] boxes of Strawberry covered chocolates and
Profit [tex]$=2.25\times} 600+2.50\times 200$[/tex]
Profit [tex]$=\$ 1850$[/tex]
This is the maximum profit that can be earned after making combination of two types of chocolates.
To learn more, refer:
https://brainly.com/question/17546009